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@@ -37,11 +37,13 @@ do
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if [ $((line_number - 50)) -lt 0 ]; then
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sed -n "1,$((line_number + 100))p" "$dir/$file" | awk '{printf("%s %s\n", NR, $0)}'
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echo "-----------------"
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- echo 'sed -n "1,'"$((line_number + 100))"'p" "'"$dir/$file"'" | awk '\''{printf("%s %s\n", NR, $0)}'\'''
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+ command="sed -n \"1,$(( $line_number + 100 ))p\" \"$dir/$file\" | awk '{printf(\"%s %s\\n\", NR, \$0)}'"
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+ echo "Executing command: $command"
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else
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sed -n "$((line_number - 50)),$((line_number + 100))p" "$dir/$file" | awk '{printf("%s %s\n", NR+'$(($line_number - 51))', $0)}'
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echo "-----------------"
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- echo 'sed -n "$((line_number - 50)),$((line_number + 100))p" "$dir/$file" | awk "{printf("%s %s\n", NR+'$(($line_number - 51))', $0)}"'
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+ command="sed -n \"$(( $line_number - 50)),$(( $line_number + 100))p\" \"$dir/$file\" | awk '{printf(\"%s %s\\n\", NR+'$(($line_number - 51))', \$0)}'"
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+ echo "Executing command: $command"
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fi
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echo "在文件 $file 中找到了字符串 '$2'，位于第 $line_number 行："
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break
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